Explosion protected Axial Piston Motors according to ATEX Directive 94/9/EC 05 18 »High start torques (full torque and pressure across the total speed range). »Drive shafts accept axial and radial loads directly. »High performance motors operate down to 1 rpm without cogging and up to a maximum of 2,000 rpm. »AEZ units designed for very arduous applications with the potential of high shocks (up to 6.3 'G' force) such a centrifuges, marine applications. »Can be fully ATEX certificated for hazardous applications (Zone 1, Zone 21 (dust) and underground use to 'M2' level (mining). Therefore applications are not only offshore but also chemical plants, machine manufacturers etc. »High overall efficiencies up to 94%.
an excellence in engineering www.jbj.co.uk/ .html hydraulic-motors These hydraulic motors have a high starting torque, ideal for instance, for safe operation of the heavy gates on the material lock in a nuclear power plant or to hand over the weighty coils in a rollingmill. Due to the low amount of revolving mass, the rotational direction can be quickly changed, a feature very important in many test benches; when performing vibration tests on motorcycle forks or when testing the adjustment of wing flaps on aircraft. The components can perform up to 50 rotational direction changes per second. An exact adherence to the specified rotational speed profile is of essential importance for many fields of application of hydraulic motors. Here is a new generation of motors, for which a significantly improved constancy of rotational speed is achieved compared to conventional motors. www.jbj.co.uk/hydraulicmotors.html »high starting torque » immediately reversible » total efficiency up to 96% »extremely low moment of inertia » low maintenance » full torque available over complete speed range »shaft end can be subjected to high radial and axial forces »only very few moving parts in the rotating group » instrument shaft may be fitted » low leakage-built in wear compensation »suitable for use with fire resistant fluids »no counterpressure necessary when operated as a motor »suitable for use as pumps with boosted system »eminently suitable for control systems »control of feed and discharge possible »may be operated in parallel »small ports are B.S.P. type G threads according to ISO 22811 »SAE Flange connection HYDRAULIC MOTORS low speed, high torque (LSHT) 01737 767493 info@jbj.co.uk www.jbj.co.uk - registered in England No: 1185469 - jbj Techniques Limited is ISO certificated, committed to international coordination & unification of industrial standards. A range of products ATEX certificated to directive 94/9/E requirements
The details contained within this catalogue are reproduced in accordance with the latest information at publication of this catalogue. Errors and Omissions Excepted Last update: 31/05/2018 Page Axial Piston Motors AE3 - AE180 SERIES AE4 series characteristics graphs ............................................................................ 12 - 14 AE40 series characteristics graphs ......................................................................... 35 - 37 AE21 series characteristics graphs ......................................................................... 25 - 27 AE10 series characteristics graphs ......................................................................... 19 - 21 AE16 series characteristics graphs ......................................................................... 22 - 24 AE22 to AE45 series specifications & dimensions .................................... 28 AE22 series characteristics graphs ......................................................................... 29 - 31 AE3 to AE180 series axial piston motors introduction .......................... 1 - 2 AE3 to AE180 series fixed geometric displacements .............................. 3 AE3 to AE45 series product code .............................................................................. 4 AE3 to AE45 series functional description ....................................................... 5 AE3 to AE5 series specifications & dimensions .......................................... 6 AE3 series characteristics graphs ............................................................................ 7 - 11 AE10 to AE21 series specifications & dimensions .................................... 18 AE32 series characteristics graphs ......................................................................... 32 - 34 AE5 series characteristics graphs ............................................................................ 15 - 17 AE45 series characteristics graphs ......................................................................... 38 - 40 AE3 to AE45 series measuring shaft & IEC adaptor flanges ............ 41
• Overall efficiencies up to 94%. • Stepless adjustable speed and torque. • IEC electric motor interfaces available. Efficient and cost saving • Low maintenance costs due to the robust design. • Energy recovery and energy storage. Performance • Using one central provider for various drive operations. • Motor internal leakage provides constant cooling of the rotating group. • Strong drive shaft capable of withstanding radial and axial loads.. • Wide speed range (3 – 5250 rpm ). • High starting torque (full torque is available across the whole speed range from zero high to max. speed). Further advantages of hydraulic drive concepts • Experienced sales and engineering department, actively involved in finding solutions for customer drive applications, be they hydraulic, pneumatic or mechanical. • Small quantity units always considered. • Involved in all hydraulic and pneumatic tasks, such as engineering hydraulic / pneumatic controls and hydraulic power units. Service from jbj Techniques Ltd and working partner Düsterloh Fluidtechnik GmbH AE21 21,3 64 76 3 2400 210 250 AE45 45,0 135 161 10 2000 210 250 AE4 4,0 12 14 5 3750 210 250 AE16 16,0 48 57 5 2500 210 250 Displacement Torque Speed Range Pressure Motor cont.* max.** min. max. cont. max. [ccm/rev] [Nm] [Nm] [rpm] [rpm] [bar] [bar] AE3 2,9 9 10 10 5250 210 250 AE5 5,1 16 19 3 3000 210 250 AE10 11,4 34 41 10 3000 210 250 AE32 31,5 95 113 5 2000 210 250 AE40 40,5 122 145 3 2000 210 250 AE22 22,5 68 81 10 2000 210 250 AE71 70,4 212 252 10 2250 210 250 AE140 141,1 425 505 5 1200 210 250 AE180 181,5 546 650 3 1000 210 250 AE125 126,7 381 454 3 1420 210 250 AE100 98,5 296 353 5 1725 210 250 cont.* max.** min. max. cont. max. [ccm/rev] [Nm] [Nm] [rpm] [rpm] [bar] [bar] AEHP40 43,7 132 158 1 2000 210 250 RMHP110 109,5 217 310 1 750 210 250 The high precision series of hydraulic motors with exceptional speed consistency, even at speed down to 1 rpm. RMHP90 88,4 174 252 1 900 210 250 Displacement Torque Speed Range Pressure Motor Axial Piston Motors AE3 - AE180 SERIES High-precision hydraulic motors 1 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony
The hydraulic motor series 71 – 125 range achieves balancing classes up to G 6.3 according to ISO 1940 part 1, due to its a specific design and AEZ precision manufacturing. This makes the AEZ motors ideal for use in rotary systems, such as centrifuges. The proven advantages of this hydraulic drive, reliability, precision and reversibility, assure cost effective operation. Axial piston motors rotational systems Rotatory hydraulic drive units » Printing and paper technology. » Manipulators. - I M2 EEx c IIC T4 Application examples... » Vehicle construction. automatic forging machines. - II 2G EEx c IIC T4 ( zone 1 ) On demand the common ATEX – versions are available for the following protection classes: This range of piston motors being characterised by their unique combination of strength of design and their precision manufacture, result in a motor of exceptional performance, reliability and reduced operational costs » The adjustment of the stroke of forge tools in the confined space of jbj Techniques develop special customer solutions for radial piston motors in combination with gear boxes, couplings, brakes and valve blocks. The IEC flange versions make these adaptable to a wide range of applications. - II 2D EEx c T4 ( zone 21 ) » Suitable for test bed applications such as vibration test beds for the automotive industry and torsional testing of material samples.. » The movement of additional tools ( drills and mouldings ) in CNC – machine shops. » Smelting and rolling mill equipment. » Machine tools. » Foundry machines. » Shipbuilding (diesel engines). » Offshore technology. » Mining equipment. » Materials handling equipment. www.jbj.co.uk/ .html hydraulicmotors » Environmental technology. Axial Piston Motors AE3 - AE180 SERIES [ccm/rev] [Nm] [Nm] [rpm] [rpm] [bar] [bar] cont.* max.** min. max. cont. max. Displacement Torque Speed Range Pressure Motor AEZ100 98,5 296 353 5 1750 250 300 AEZ71 70,4 212 252 10 2250 250 300 AEZ125 126,7 381 454 3 1420 250 300 2 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony
LSHT Hydraulic Motors AE3 - AE180 Series Axial Piston Motors 3 Fixed Displacement Motor (fixed geometric displacement) www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony 71 70.4 1.008 252.0 10 2250 210 250 315 33.2 39.6 10 11.4 0.164 40.9 10 300 210 250 315 7.2 8.5 140 141.1 2.022 505.4 5 1200 210 250 315 35.6 42.3 5 5.1 0.074 18.4 3 3000 210 250 315 3.2 3.8 125 126.7 1.814 453.6 3 1420 210 250 315 37.8 45.0 4 4.0 0.057 14.3 5 3750 210 250 315 3.2 3.8 16 16.0 0.229 57.3 5 2500 210 250 315 8.4 10.0 21 21.3 0.305 76.3 3 2400 210 250 315 10.7 12.8 32 31.5 0.451 112.8 5 2000 210 250 315 12.5 15.0 40 40.5 0.580 145.0 3 2000 210 250 315 16.0 19.0 45 45.0 0.645 161.2 10 2000 210 250 315 17.8 21.0 22 22.5 0.322 80.6 10 2000 210 250 315 9.0 11.0 3 2.9 0.041 10.2 10 5250 210 250 315 3.2 3.8 100 98.5 1.411 352.8 5 1725 210 250 315 35.7 42.5 180 181.5 2.599 649.8 3 1000 210 250 315 38.1 45.4 Axial Piston Motor Type AE Displacement Vg 3 cm /rev Torque Tspec Nm/bar Tmax Nm/bar Speed Range N * min rpm nmax rpm Continuous Pressure pcont bar Maximum Pressure pmax bar Peak Pressure ppeak bar Power Pcont kW Pintermit kW p Continuous power (at 10 bar back line pressure); if p will be over extended for a long time, it is recommended to flush the engine by using cold operation cont cont fluid. »High initial torque (full torque is available across the whole speed range from zero high to maximum speed). p limitation by p . andp 10% power-on time with regards to one hour operating time. max intermit max * Speed less then 1 rpm can be achieved by using an electro hydraulic servo valve. p limitation by p cont cont p highest pressure at which the components will remain functional. peak p Power which can be supplied temporary based on max. 10% power-on time with regards to one hour operating time. intermit Performance: »Great speed range (3 – 5,250 rpm). Further advantages of hydraulic drive concepts: »Persistent motor cooling with operating medium Efficient and cost saving: »Overall efficiencies up to 94% »Energy recovery and energy storage » Low maintenance costs due to the robust design »Drive shaft withstands radial and axial loads. »Using one central provider for various drive operations »Stepless adjustable speed and torque.
4 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony (optional / not suitable for combination with connections B and B5) Class AE 3-5 AE 10-21 AE 22-45 A Displacement 3 4 5 10 16 21 22 32 40 45 B Drive shaft Z: Cylindrical drive shaft with feather key ● ● ● ● ● ● ● ● ● ● Z8: Cylindrical drive shaft ø28 x 50 long with feather key - - - - - - ● ● ● ● suitable in combination with F16 flange acc. IEC-norm Z68: Cylindrical drive shaft ø24 x 50 long with feather key - - - - - - ● ● ● ● W2: Conical drive shaft with grub screw - - - ● ● ● - - - - F: four hole flange ● ● ● ● ● ● ● ● ● ● F1: three hole flange - - - - ● ● ● - - - - F16: four hole flange / design CEI-IEC 72-2 - - - ○ ○ ○ ● ● ● ● B5 IEC 100/112 Standard for special/aggressive operation fluids. H Special version S: Several customized solutions are available on request. ● ● ● ● ● ● ● ● ● ● Z76: Cylindrical drive shaft ø19 x 36 long with feather key - - - ● ● ● - - - - D Control version *: Not specified (translatory steering disc) ● ● ● ● ● ● ● ● ● ● A1: Connection face for valve block mountings - - - ● ● ● ● ● ● ● suitable in combination with F15 flange acc. IEC-norm E Sealing material *: Not specified (NBR sealing) ● ● ● ● ● ● ● ● ● ● V: FPM sealing: Suitable for a high temperature rang as well as ● ● ● ● ● ● ● ● ● ● G Flange version *: Not specified / without flange - - - - - - ● ● ● ● F15: four hole flange / design CEI-IEC 72-2 - - - ● ● ● ● ● ● ● (optional) II2D: II 2D c T4 ● ● ● ● ● ● ● ● ● ● shaft version M39: Cylindrical shaft ø10 without centring - - - ● ● ● ● ● ● ● B: Axial connection thread (metric) ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ E5: Self readjusting clearance control version ● ● ● ● ● ● ● ● ● ● I ATEX II2G: II 2G c T4 ● ● ● ● ● ● ● ● ● ● suitable in combination with F15 flange acc. IEC-norm C Connections A: Radial connection thread - - - ○ ○ ○ ● ● ● ● E2: Servo quality, reduced clearance, enhanced activation piloting ● ● ● ● ● ● ● ● ● ● A34: Connection face with connection thread - - - ● ● ● - - - - K: Male involute splined drive shaft - - - ○ ○ ○ ○ ○ ○ ○ and concentric run-out characteristics B5: Axial connection thread (inch) ● ● ● ● ● ● ● ● ● ● (temperature adaptability, reduction of intern leakage) F Measuring M: Cylindrical shaft ø10 with centring - - - ● ● ● ● ● ● ● B5 IEC 80 (AE 10-21) / B5 IEC 90 (AE 22-45) IM2: I M2 c T4 ● ● ● ● ● ● ● ● ● ● Appropriate product codes will be assigned by the company. A B C D E F G H I N Product code: AE LSHT Hydraulic Motors AE3 - AE45 Series Product Code Key:● = available; ○ = on request; - = not available
(4) Drive case (5) Pressure port 1 (6) Pressure port 2 (7) Outer steering zone (8) Inner steering zone (9) Steering disc (10) Deep groove ball thrust bearing (11) Eccentric (12) Pilot hole (1) Piston (2) Wobbel plate (3)Drive shaft (13) Leakage port Functional description Via both pressure ports (5/6) and the leakage port (13) is the motor linked to the hydraulic system. By pressurising one of the pressure ports (5/6) the operation medium gets into the steering zone (7/8) of themotor. Depending on port (5/6) and therefore on the pressurized steering zone (7/8), the rotation direction of themotor will change. Due to the steering unit (7/8), high pressurized operation fluid gets to the pistons (1) and forces them to extend against the wobble plate (2). Because of the draft angle of the wobble plate (2), the piston load results by resolution of a force and lever arm into a torsional moment. During rotation movement the fixed with the shaft (3) mounted eccentric (11) and its steering discs (9) overtravels the different pilot holes (12) which occurs in a continuous opening and closing. The pistons fully extend based on the draft angle of the wobble plate, then they are forced by the new high pressure to run back into the drive case (4). This effect causes the now low pressurized operation medium to flow via the other pressure port (5/6) back to the HPU's (Hydraulic Power Unit) tank. Functional descriptionwobble plate The wobble plate (2) is fixed to the drive shaft (3) mounted plate with a certain draft angel. By feeding the motor with operation medium, the parallel to the drive shaft arranged pistons (1) start to fulfill an axial load which forces the wobble plate (2) and therefore the pivoted drive shaft (3) to turn. Functional description of these axial pistonmotors All mentioned hydraulic motors in this catalogue are designed with a fixed displacement and work according to the wobble plate principle. The purpose of a hydraulic drive is to transfer hydraulic power in to mechanical power. Hydraulic power is created by the hydraulic volume flow as well as the pressure difference which is pending between the motors inlet and outlet. The mechanical power results from the speed, torque and efficiency of the motor which can be directly applied from the drive shaft. The required pressure difference in order to turn the shaft will automatically adjust itself to the needed torque at the drive shaft specified by the application. Therefore the needed pressure difference will always be load-dependent. The engine speed on the other hand is directly controlled by the feed of the volume flow of the hydraulic pump. LSHT Hydraulic Motors AE3 - AE45 Series Axial Piston Motors 5 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony
6 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE3 - AE5 Technical Specifications & Dimensions Max. intermittent power P . kW 3.8 3.8 3.8 interm Max. continuous power P . kW 3.2 3.2 3.2 cont Mass m kg 3.4 3.4 3.4 Temperature range of pressure medium Θ °C -30 to +80 2 Viscosity u mm /s 18 till 1000, recommended: 30 till 50 2 Mass moment of intertia J kgm 0.000045 0.000045 0.000045 Operating speed range n rpm 10-5250 5-3750 3-3000 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Nominal size NS 3 4 5 Max. torque T . Nm 10.25 14.25 18.5 max 3 Displacement V cm /rev 2.859 4.003 5.146 g Theor. specific torque T . Nm/bar 0.046 0.064 0.082 spec.theor Average specific torque T . Nm/bar 0.041 0.057 0.074 spec.aver Continuous torque T . Nm 8.6 12 15.5 cont Inlet pressure, max. cont. p . bar 210 210 210 cont max. p . bar 250 250 250 max peak p bar 315 315 315 peak Total pressure p bar 315 315 315 total Leakage pressure, max. p . bar 1.5 1.5 1.5 leak Example of type designation: AE (3 till 5) ZB5FN Example of type designation: AE (3 till 5) ZBFN P . = Power, which may be demanded temporarily (max. 10% duty cycle / hour). interm p = peak pressure, where the components remain safe in function. peak P . = Continuous power (at maximal 10 bar outlet pressure). Motor flushing must be carried out above P . cont cont p . = maximal admissible operating pressure at limitation P . and max. 10% duty cycle / hour max interm p = maximum permissible pressure combined out of inlet and outlet pressure. total p . = admissible continuous pressure at limitation to p cont cont
Torque curve x F S1 S2 admissible range for intermittent operation without ushing admissible range for continuous operation without ushing Example: Given: F=750N;x=18mm;∆p=150bar Wanted: Shaft strength Generate intercept point S1 by using radial load F and shaft gap X. Now, S2 will be determined by using S1 and the pressure difference ∆p. In case, S2 is located within the hachure’s sector, shaft will be fatigue endurable. 7 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE3 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation
8 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE3 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r S2 S3 S1 Gap: X = 18mm Speed: n = 2,000 rpm Pressure difference: Δp = 150 bar Given: Radial load: F = 0.75 kN r Wanted: Service life radial bearing. Graph to determine service life of radial bearing: To determine service life of bearing, use radial loadF = 0,75 kNand gapX = 18 mm in order to find intercept r point S1. By usingS1, draw a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 2000 rpm, intercept point S3 is found. By drawing a vertical line from S3 to the x-axis, you can determine the service life of the bearing Lh10 by approx. 3,100 hours.
9 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE3 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r S2 S3 S1 Given: Radial load: F = 0.75 kN r Gap: X = 18mm Graph to determine service life of radial bearing: Pressure difference: Δp = 150 bar Wanted: Service life radial bearing. Speed: n = 2,000 rpm To determine service life of bearing, use radial loadF = 0,75 kNand gapX = 18 mm in order to find intercept point S1. By r usingS1, draw a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 2000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 3,100 hours.
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing S1 S2 S3 x F r S1 Pressure difference: Δp = 150 bar Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =150 bar to speed curven = 2000 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx. 60,000 hours. Gap: X = non-existent Speed: n = 2000 rpm Given: Radial load: F = non-existent Wanted: Service life radial bearing. Graph to determine service life of axial bearing: Pressure difference: Δp = 150 bar Given: Radial load: F = 0,75 kN Gap: X = 18mm Wanted: Service life radial bearing Graph to determine service life of radial bearing: To determine service life of bearing, use radial load F = 0,75 kNand gapX = 18 mm in order to find intercept point S1. By usingS1, r draw a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 2000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 127,950 hours. Speed: n = 2000 rpm 10 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE3 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless
11 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE3 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r S2 S3 S1 To determine service life of bearing, use radial loadF = 0,75 kNand gapX = 18 mm in order to find intercept point S1. By r usingS1, draw a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 2000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 3,100 hours. Wanted: Service life radial bearing. Graph to determine service life of radial bearing: Pressure difference: Δp = 150 bar Speed: n = 2,000 rpm Given: Radial load: F = 0.75 kN r Gap: X = 18mm
Torque curve 12 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE4 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation admissible range for intermittent operation without ushing admissible range for continuous operation without ushing x F S1 S2 Example: Given: F=500N;x=18mm;∆p=150bar Wanted: Shaft strength Generate intercept point S1 by using radial load F and shaft gap X. Now, S2 will be determined by using S1 and the pressure difference ∆p. In case, S2 is located within the hachure’s sector, shaft will be fatigue endurable.
13 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE4 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Given: Radial load: Fr = 0,5 kN Gap: X = 18mm Pressure difference: Δp = 150 bar To determine service life of bearing, use radial loadF = 0.5 kNand gapX = 18mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 150 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 1000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 14,500 hours. Graph to determine service life of radial bearing: Wanted: Service life radial bearing Speed n = 1000 rpm
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r Pressure difference: Δp = 150 bar Gap: X = non-existent Given: Radial load: F = non-existent Speed: n = 1000 rpm Graph to determine service life of axial bearing: Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =150 bar to speed curven = 1000 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 32,000 hours. Wanted: Service life radial bearing. Given: Radial load F = 0.5 kN Gap: X = 18mm Speed n = 1000 rpm Wanted: Service life radial bearing To determine service life of bearing, use radial loadF = 0.5 kNand gapX = 14 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 250 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 2000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 110,000 hours. Pressure difference: Δp = 150 bar Graph to determine service life of radial bearing: 14 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE4 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless
Torque curve 15 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE5 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation x F Example: Given: F=500N;x=18mm;∆p=150bar Wanted: Shaft strength Generate intercept point S1 by using radial load F and shaft gap X. Now, S2 will be determined by using S1 and the pressure difference ∆p. In case, S2 is located within the hachure’s sector, shaft will be fatigue endurable.
16 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE5 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Speed n = 1000 rpm Graph to determine service life of radial bearing: Given: Radial load: Fr = 0.5 kN To determine service life of bearing, use radial loadF = 0.5 kNand gapX = 18mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 150 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 1000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 14,500 hours. Gap: X = 18mm Pressure difference: Δp = 150 bar Wanted: Service life radial bearing
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 17 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE5 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Graph to determine service life of axial bearing: Wanted: Service life radial bearing. Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =150 bar to speed curven = 1000 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 15,600 hours. Given: Radial load: F = non-existent Gap: X = non-existent Speed: n = 1000 rpm Pressure difference: Δp = 150 bar Wanted: Service life radial bearing Gap: X = 18mm Speed n = 1000 rpm Pressure difference: Δp = 150 bar To determine service life of bearing, use radial loadF = 0.5 kNand gapX = 18 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 1000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 52,000 hours. Given: Radial load F = 0.5 kN Graph to determine service life of radial bearing:
18 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE10 - AE21 Technical Specifications & Dimensions 3 Displacement V cm /rev 11.435 16.009 21.308 g Continuous torque T . Nm 34.4 48.1 64.1 cont Average specific torque T . Nm/bar 0.164 0.229 0.305 spec.aver Inlet pressure, max. cont. p . bar 210 210 210 cont Theor. specific torque T . Nm/bar 0.182 0.255 0.339 spec.theor 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless max. p . bar 250 250 250 max peak p bar 315 315 315 peak Nominal size NS 10 16 21 Total pressure p bar 315 315 315 total Leakage pressure, max. p . bar 1.5 1.5 1.5 leak Max. continuous power P . kW 7.7 8.1 10.7 cont 2 Mass moment of intertia J kgm 0.000035 0.000035 0.000035 Mass m kg 12.8 12.8 12.8 Temperature range of pressure medium Θ °C -30 to +80 2 Viscosity u mm /s 18 till 1000, recommended: 30 till 50 Max. intermittent power P . kW 9.2 9.6 12.8 interm Operating speed range n rpm 10-3000 5-2500 3-2400 Max. torque T . Nm 41 57.3 76.3 max p = maximum permissible pressure combined out of inlet and outlet pressure. total p . = maximal admissible operating pressure at limitation P . and max. 10% duty cycle / hour max interm p . = admissible continuous pressure at limitation to p cont cont P . = Power, which may be demanded temporarily (max. 10% duty cycle / hour). interm p = peak pressure, where the components remain safe in function. peak P . = Continuous power (at maximal 10 bar outlet pressure). Motor flushing must be carried out above P . cont cont
Torque curve 19 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE10 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation
20 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE10 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Graph to determine service life of radial bearing: Given: Radial load: Fr = 2.0 kN Gap: X = 36mm Speed n = 2000 rpm Wanted: Service life radial bearing Pressure difference: Δp = 200 bar To determine service life of bearing, use radial loadF = 2.0 kNand gapX = 36mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 200 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 2000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 6,500 hours.
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 21 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE10 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Graph to determine service life of axial bearing: Speed: n = 2000 rpm Pressure difference: Δp = 200 bar Given: Radial load: F = non-existent Gap: X = non-existent Wanted: Service life radial bearing. Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =200 bar to speed curven = 2000 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 10,000 hours. Graph to determine service life of radial bearing: Wanted: Service life radial bearing To determine service life of bearing, use radial loadF = 2.0 kNand gapX = 36 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 200 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 2000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 11,000 hours. Given: Radial load F = 2.0 kN Pressure difference: Δp = 200 bar Gap: X = 36mm Speed n = 2000 rpm
Torque curve 22 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE16 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation x F Example: Given: F=2000N;x=36mm;∆p=150bar Wanted: Shaft strength Generate intercept point S1 by using radial load F and shaft gap X. Now, S2 will be determined by using S1 and the pressure difference ∆p. In case, S2 is located within the hachure’s sector, shaft will be fatigue endurable.
23 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE16 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Gap: X = 36mm Speed n = 1000 rpm Pressure difference: Δp = 150 bar Graph to determine service life of radial bearing: Given: Radial load: Fr = 2.0 kN To determine service life of bearing, use radial loadF = 2.0 kNand gapX = 36mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 150 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 1000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 9,500 hours. Wanted: Service life radial bearing
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 24 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE16 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Given: Radial load: F = non-existent Gap: X = non-existent Pressure difference: Δp = 150 bar Speed: n = 1000 rpm Wanted: Service life radial bearing. Graph to determine service life of axial bearing: Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =150 bar to speed curven = 1000 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 13,200 hours. To determine service life of bearing, use radial loadF = 2.0 kNand gapX = 36 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 1000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 15,300 hours. Wanted: Service life radial bearing Graph to determine service life of radial bearing: Given: Radial load F = 2.0 kN Gap: X = 36mm Pressure difference: Δp = 150 bar Speed n = 1000 rpm
Torque curve 25 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE21 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation x F Example: Given: F=2000N;x=36mm;∆p=100bar Wanted: Shaft strength Generate intercept point S1 by using radial load F and shaft gap X. Now, S2 will be determined by using S1 and the pressure difference ∆p. In case, S2 is located within the hachure’s sector, shaft will be fatigue endurable.
26 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE21 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Speed n = 1000 rpm Pressure difference: Δp = 100 bar Given: Radial load: Fr = 2.0 kN Gap: X = 36mm To determine service life of bearing, use radial loadF = 2.0 kNand gapX = 36mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 100 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 1000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 9,500 hours. Wanted: Service life radial bearing Graph to determine service life of radial bearing:
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 27 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE21 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Given: Radial load: F = non-existent Gap: X = non-existent Pressure difference: Δp = 100 bar Wanted: Service life radial bearing. Graph to determine service life of axial bearing: Speed: n = 1000 rpm Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =100 bar to speed curven = 1000 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 21,500 hours. Gap: X = 36mm Given: Radial load F = 2.0 kN Pressure difference: Δp = 100 bar Speed n = 1000 rpm To determine service life of bearing, use radial loadF = 2.0 kNand gapX = 36 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 100 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 1000 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 23,400 hours. Wanted: Service life radial bearing Graph to determine service life of radial bearing:
28 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE22 - AE45 Technical Specifications & Dimensions Inlet pressure, max. cont. p . bar 210 210 210 210 cont Leakage pressure, max. p . bar 1.5 1.5 1.5 1.5 leak Theor. specific torque T . Nm/bar 0.358 0.501 0.645 0.716 spec.theor Total pressure p bar 315 315 315 315 total 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless 3 Displacement V cm /rev 22.501 31.501 40.502 45.002 g Operating speed range n rpm 10-2000 5-2000 3-2000 10-2000 Max. intermittent power P . kW 11.0 15.0 19.0 21.5 interm Average specific torque T . Nm/bar 0.322 0.451 0.580 0.645 spec.aver peak p bar 315 315 315 315 peak 2 Mass moment of intertia J kgm 0.00195 0.00195 0.00195 0.00195 max. p . bar 250 250 250 250 max Temperature range of pressure medium Θ °C -30 to +80 Max. torque T . Nm 81 113 145 161 max Nominal size NS 22 32 40 45 2 Viscosity u mm /s 18 till 1000, recommended: 30 till 50 Continuous torque T . Nm 68 95 122 135 cont Max. continuous power P . kW 9.0 12.5 16.0 18.0 cont Mass m kg 22 22 22 22 p . = admissible continuous pressure at limitation to p cont cont p . = maximal admissible operating pressure at limitation P . and max. 10% duty cycle / hour max interm p = peak pressure, where the components remain safe in function. peak P . = Continuous power (at maximal 10 bar outlet pressure). Motor flushing must be carried out above P . cont cont P . = Power, which may be demanded temporarily (max. 10% duty cycle / hour). interm p = maximum permissible pressure combined out of inlet and outlet pressure. total Example of type designation: AE (22 till 45) ZAN Example of type designation: AE (22 till 45) ZA1FN
Torque curve 29 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE22 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation x F S1 S2 admissible range for intermittent operation without ushing admissible range for continuous operation without ushing Example: Given: F=15000N;x=25mm;∆p=200bar Wanted: Shaft strength Generate intercept point S1 by using radial load F and shaft gap X. Now, S2 will be determined by using S1 and the pressure difference ∆p. In case, S2 is located within the hachure’s sector, shaft will be fatigue endurable.
30 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE22 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Pressure difference: Δp = 200 bar Wanted: Service life radial bearing Given: Radial load: Fr = 4.0 kN Speed n = 200 rpm To determine service life of bearing, use radial loadF = 4.0 kNand gapX = 50mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 100 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 15,300 hours. Graph to determine service life of radial bearing: Gap: X = 50mm
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 31 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE22 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =200 bar to speed curven = 200 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 33,000 hours. Given: Radial load: F = non-existent Pressure difference: Δp = 200 bar Wanted: Service life radial bearing. Speed: n = 200 rpm Gap: X = non-existent Graph to determine service life of axial bearing: Gap: X = 50mm Pressure difference: Δp = 200 bar Speed n = 200 rpm Wanted: Service life radial bearing Given: Radial load F = 2.0 kN Graph to determine service life of radial bearing: To determine service life of bearing, use radial loadF = 4.0 kNand gapX = 50 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 200 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 154,000 hours.
32 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE32 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Torque curve Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation
33 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE32 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Given: Radial load: Fr = 3.75 kN Gap: X = 50mm Pressure difference: Δp = 150 bar To determine service life of bearing, use radial loadF = 3.75 kNand gapX = 50 mm in order to find intercept point S1. By r usingS1, draw a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 19,000 hours. Speed n = 200 rpm Wanted: Service life radial bearing Graph to determine service life of radial bearing:
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 34 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE32 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Gap: X = non-existent Speed: n = 200 rpm Wanted: Service life radial bearing. Given: Radial load: F = non-existent Graph to determine service life of axial bearing: Pressure difference: Δp = 150 bar Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =150 bar to speed curven = 200 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 30,000 hours. Graph to determine service life of radial bearing: To determine service life of bearing, use radial loadF = 3.75 kNand gapX = 50mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 40,000 hours. Given: Radial load F = 3.75 kN Gap: X = 50mm Pressure difference: Δp = 150 bar Speed n = 200 rpm Wanted: Service life radial bearing
35 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE40 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Torque curve Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation
36 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE40 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r Given: Radial load: Fr = 7.0 kN Gap: X = 15mm Wanted: Service life radial bearing Graph to determine service life of radial bearing: Pressure difference: Δp = 250 bar Speed n = 200 rpm To determine service life of bearing, use radial loadF = 7.0 kNand gapX = 15mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 250 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 4,400 hours.
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 37 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE40 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Graph to determine service life of axial bearing: Gap: X = non-existent Pressure difference: Δp = 150 bar Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =150 bar to speed curven = 200 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 14,500 hours. Speed: n = 200 rpm Given: Radial load: F = non-existent Wanted: Service life radial bearing. Gap: X = 15mm Given: Radial load F = 7.0 kN Speed n = 200 rpm Wanted: Service life radial bearing To determine service life of bearing, use radial loadF = 7.0 kNand gapX = 15 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 84,000 hours. Pressure difference: Δp = 150 bar Graph to determine service life of radial bearing:
38 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE45 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Torque curve Hydraulic and mechanical efficiency by % Overall leakage No-load characteristic Shaft strength calculation
39 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE45 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Life expectancy-nomogram of drive shaft faceing radial bearing x F r To determine service life of bearing, use radial loadF = 5.0 kNand gapX = 15mm in order to find intercept point S1. By using r S1, draw a vertical line to pressure curves Δp = 150 bar. From this, intercept point S2 can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 7,500 hours. Given: Radial load: Fr = 5.0 kN Graph to determine service life of radial bearing: Gap: X = 50mm Wanted: Service life radial bearing Pressure difference: Δp = 150 bar Speed n = 200 rpm
Life expectancy-nomogram of control unit faceing radial bearing Life expectancy-nomogram of axial bearing x F r 40 www.jbj.co.uk/hydraulic-motors.html #DriveLineHarmony LSHT Hydraulic Motors AE45 Series Characteristics Graphs 2 All parameters at u = 32 mm /s; Θ = 40°C; outlet = pressureless Graph to determine service life of axial bearing: Pressure difference: Δp = 150 bar Gap: X = non-existent Given: Radial load: F = non-existent Wanted: Service life radial bearing. Axial bearings are not able to receive any radial force. In order to determine service life of bearing, draw a horizontal line from the Y-axis Δp =150 bar to speed curven = 200 rpm. By drawing a vertical line from intercept point S1 to the X-axis, you can determine the service life of the bearingLh10by approx 11,000 hours. Speed: n = 200 rpm Given: Radial load F = 7.0 kN Pressure difference: Δp = 150 bar Speed n = 200 rpm Wanted: Service life radial bearing Graph to determine service life of radial bearing: To determine service life of bearing, use radial loadF = 5.0 kNand gapX = 50 mm in order to find intercept point S1. By usingS1, draw r a vertical line to pressure curvesΔp = 150 bar. From this, intercept point S2can be determined. By drawing a horizontal line to speed curven = 200 rpm, intercept point S3 is found. By drawing a vertical line fromS3 to the x-axis, you can determine the service life of the bearingLh10by approx. 52,000 hours. Gap: X = 15mm
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